2x^2-2x-330=0

Solution for 2x^2-2x-330=0 equation:

2x^2-2x-330=0

a = 2; b = -2; c = -330;
Δ = b2-4ac
Δ = -22-4·2·(-330)
Δ = 2644
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2644}=\sqrt{4*661}=\sqrt{4}*\sqrt{661}=2\sqrt{661}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2\sqrt{661}}{2*2}=\frac{2-2\sqrt{661}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2\sqrt{661}}{2*2}=\frac{2+2\sqrt{661}}{4}
$